Question
In Exercises $21-28$ , sketch the circle. Identify its center and radius. $$x^{2}-6 x+y^{2}+6 y+14=0$$
Step 1
The general form of a circle equation is $(x-h)^2 + (y-k)^2 = r^2$, where $(h,k)$ is the center of the circle and $r$ is the radius. The given equation is $x^{2}-6x+y^{2}+6y+14=0$. We can rewrite this as $(x^2 - 6x) + (y^2 + 6y) = -14$. Show more…
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