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In Exercises 21 and $22,$ find a parametric equation of the line $M$ through $\mathbf{p}$ and $\mathbf{q} \cdot[\text { Hint: } M \text { is parallel to the vector } \mathbf{q}-\mathbf{p} . \text { See the }$ figure below. $$\mathbf{p}=\left[\begin{array}{r}{2} \\ {-5}\end{array}\right], \mathbf{q}=\left[\begin{array}{r}{-3} \\ {1}\end{array}\right]$$

$x=p+t(q-p)$$x=\left[\begin{array}{c}{2} \\ {-5}\end{array}\right]+t\left[\begin{array}{c}{-5} \\ {6}\end{array}\right]$

Algebra

Chapter 1

Linear Equations in Linear Algebra

Section 5

Solution Sets of Linear Systems

Introduction to Matrices

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Lectures

01:32

In mathematics, the absolu…

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In Exercises 21 and $22,$ …

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For the following exercise…

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Find parametric equations …

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okay. And this question of figure is given. That is excellent. XTO So p Victor is here. Que victories. Hair minus p is here and a play line and passes through B and Q and resultant off Q minus. B will be here. Okay. And water that, given the data, the P equals two to minus five. Put minus five and cubicles toe minus 31 Okay, on from the hand am is parallel to the vector. Q minus B dissector on from the equation three. The Parametric Rhetoric Question off a line through a parallel to be that will be X equals toe be T Q minus p. Okay, so we help us all this X equals two. We will put the value of a fast be this plus T and Q minus 31 minus beer too. So minus five. Okay, so for solving this, we get X equals two Gu minus five. Bless. Be minus 56 Okay. And that is our final. I'm set. Thank you.

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