00:01
Okay, so when i'm given an equation like this, my first step is i want to get the trick function by itself.
00:06
What is the trick function? sign of x.
00:09
So first i want to subtract 1 from both sides, square a 2 times sine of x equals 0 minus 1 is negative 1.
00:16
How do i get the trick function completely by itself, divide by the square to 2? okay, so sine of x equals negative 1 over the square root of 2.
00:27
But let's say i wanted to rationalize the denominator.
00:31
I've multiplied by the square to two over the square to two, right? this will be negative square to two over the square root of four, and the square root of four is just two.
00:40
So my new equation, that is the same identical to my original equation, since i use the properties of equality, will be sine of x equals negative square to two over two.
00:53
Okay.
00:54
So now my second step is where is this true? well, first, sign is related to the y -axis, and it is negative.
01:04
Where is the y -axis negative? well, when it's below the x -axis, so in the third or the fourth quadrant.
01:12
And then what is the reference angle when sine is squared a 2 over 2? well, my reference angle will be in radiant pi over 4...
