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Problem 25 Easy Difficulty

In Exercises 25-34, use the matrix capabilities of a graphing utility to find the inverse of the matrix (if it exists).

$\left[ \begin{array}{r} 1 & 2 & -1 \\ 3 & 7 & -10 \\ -5 & -7 & -15 \end{array} \right]$


$A^{-1}=\left[ \begin{array}{ccc}{-175} & {37} & {-13} \\ {95} & {-20} & {7} \\ {14} & {-3} & {1}\end{array}\right]$


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Video Transcript

I'm going to be using the free open source computer. Ouch! Persistent or C A s called Maxima for solving these problems were less us to do it with the computer. So imax about you can enter a matrix in a couple of ways so we can click on algebra. And if we want to enter matrix, we can do so. We have a three by three so we can use a little table here to say 12 minus one. Really seven minus 10 minus five. Mine seven. Find this. 15 you say OK, and then converted it into maximum notation and enters the matrix. Likewise, we could go up here and say in part matrix and issues the command to invert the previous make fix, and here is our answer.