in-exercises-25-and-26-find-the-circumference-of-the-circle-with-the-given-equation-write-the-circ-2

Question

In Exercises 25 and $26,$ Find the circumference of the circle with the given equation. Write the circumference in terms of $\pi .$
$(x=2)^{2}=(y-3)^{2}=9$

Georgiann Andersen · Accepted Answer

Okay, We have asked to d&#x27;oh Question 26 and we need to figure out there asking us what the circumference is in terms of pie. So they give you the equation. I have this. Okay, so we know that the equation of a circle is going to be like the standard equation squared. Plus why, minus b squared equals the radio radius squared. So, looking at the equation that gave us we can tell that the radius squared is gonna be nine. So the radius, the square root of nine is going to be three. So that&#x27;s gonna be three units. Circumference is two pi r. So we&#x27;re gonna take two times the pi times, the three, and it&#x27;s gonna be six pie units. That&#x27;s your answer.

Ali Soave · Answer

so we know that these equation of a circle gives us the radius. With this last number, we can take the square root of this number and that gives us the radius, which would be four. So if we use our circumference, Formula two times really is times pi playing in 42 times four is eight times pi would be our circumference.

Gianna Calciano · Answer

the final quadrant dis lines, and you simply need to plot the point. So for negative to six, you go to left to from the origin and up. Six. As you can see, this last in quadrant two.

Christopher Stanley · Answer

here. We want to find the radius of this circle, given that the circle passes through the 0.25 now that passes through the 0.25 What that tells us is that if we put two in Forex employed five in for. Why that this is going to give us a true statement. And so if we just plug those in, we can solve this for art Tu minus 20 zero Sparta zero. So this first part here just goes away. Five minus three is two to square. This force we have four is equal to r squared. And so that tells us our is to that&#x27;s all. The radius of this circle is too.

Mary Brese · Answer

I have a circle where the equation is X minus eight Quantity squared plus y plus five quantity squared equals seven. So riding that in the original standard form, we&#x27;ve got X minus eight quantity squared. Which means our H value for the center is eight. However, why plus five came from why minus a negative five. So negative five is R K value for the center and seven. Um is the r squared? I&#x27;m sorry, R squared is part of the equation, which means if seven is r squared, then the square root of seven is are so this is square root of seven squared. Um, so now I need that our value. Actually, I need r squared and are because I&#x27;m gonna find the area and the circumference of the circle, and I&#x27;m gonna leave them in terms of pie. So the area of a circle the formula is pi times r squared. And we know that our squared is seven. So that means our area is seven pi. If we were to add units, it would be units squared because it&#x27;s area. Our circumference formula is two pi r. So we need our radius for this formula So circumference is two times pi times the square root of seven. And that means that we could ride it as two pi square root of seven units or some people like to put all of the numerical before the symbol, so it might be written as two square roots of seven PI units.

Mary Brese · Answer

I have a circle whose equation is X plus two quantity squared. Well, I minus seven quantity squared equals nine. If the center is at HK, that means our h is negative too, because this would be X minus negative two squared and R. K is seven because we already have Loy minus seven squared and our radius is three because nine is three squared. Well, we&#x27;re going to focus on the Radius because I&#x27;m gonna find the area and the circumference of the circle in terms of pie. So area the formula is pi r squared and therefore we&#x27;re gonna fill in our radius and that gives this nine pi. If we were gonna put units, it would be unit squared. So that&#x27;s the area. In terms of pie, the circumference is two pi r. So we have two times pi times three, which gives us six pie and circumference is measured in units

Problem

USING STRUCTURE A semicircle has endpoints $(-2,-…

Problem 26 Easy Difficulty

In Exercises 25 and $26,$ Find the circumference of the circle with the given equation. Write the circumference in terms of $\pi .$
$(x=2)^{2}=(y-3)^{2}=9$

Answer

6$\pi$

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Ron Larson, Laurie Boswell

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Megan C.

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(A few) Circle Theorems

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6$\pi$

Geometry A Common Core Curriculum

Megan C.

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Angles and Cirlce Theorems with chords and tangents

Ron Larson, Laurie BoswellGeometry A Common Core Curriculum

Megan C.

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Kristen K.

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Ron Larson, Laurie Boswell

Geometry A Common Core Curriculum