00:01
All right, here on this problem, we have these two equations, and we want to solve this system of equations.
00:05
And we're told to do it by graphing.
00:09
And so we need to graph each of these.
00:12
Now, it's top equation i'm going to graph in red.
00:15
If you'll notice, that's a circle with the center at 2, negative 3, so we put our center on there.
00:22
That right -hand side of the equation is 4, so our radius is 2.
00:26
And so from that center, you need to go 2 in every direction, and then draw that circle.
00:38
Now, for this bottom equation, we have y equals x minus 3, and so i'll put that in blue.
00:42
And it's a line with a y intercept of negative three and a slope of one so we go up one over one up one over one and so on and so we're talking about that line now the solution to a system of equations is the point or points where the graphs intersect and so that's what we care about here so we've got this first point down there that's zero negative three and then a second one up here and that looks like two negative one and so these are these are going to be our two solutions, 0 negative 3 and 2 negative 1.
01:21
Now we do need to check them.
01:23
Checking them just means plugging them into these two equations and making sure they work.
01:28
I'm going to start with 2 negative 1...