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In Exercises $27 - 30 ,$ integrate $f$ over the given curve.

$$

\begin{array} { l } { f ( x , y ) = x ^ { 2 } - y , \quad C : \quad x ^ { 2 } + y ^ { 2 } = 4 \text { in the first quadrant from } } \\ { ( 0,2 ) \text { to } ( \sqrt { 2 } , \sqrt { 2 } ) } \end{array}

$$

$\pi-2-2 \sqrt{2}$

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Nicolas W.

April 3, 2021

Not only did you not show your work for the parameterization, but you parameterized it incorrectly.

Johns Hopkins University

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Oregon State University

University of Nottingham

Oh, has function this to assign See to co sign t 40 from zero to well, your pie. So the march of the derivative would be too. Using the identity of the children is a function. We're the nine to go f oversee. Forget the data. We're gonna have zero to have high. I'm sorry. 0 to 1 0/4 Bi, You saw that? We have for sun t squared on this tickles nt Did she? Tom's too. So the answer is plying minus two minus to Times Square to

University of Illinois at Urbana-Champaign