00:01
In this question, we have the position vector of a particle that is rt is equals to 2.
00:12
Cosine 3 t, 2 .6 .4t.
00:21
We are required to find its velocity vector and acceleration vector.
00:25
So let's see how to solve this question.
00:28
We know that the formula to calculate the velocity vector is given by vt is equal to first derivative of or d by dt of position vector rt.
00:45
Hence, on the basis of this formula, we can conclude that velocity vector vt will be equals to d by dt of 2, cosine 3t, comma, 2, sine 4t.
01:06
So this will be equals to d by dt of 2 cosine 3t.
01:17
D by d t of 2 sine 40.
01:27
Now let's differentiate these functions.
01:31
We know that the differentiation of cosine x is equals to minus sinex and the differentiation of sine x is equal to cosine x...