Question
In Exercises $27-80,$ verify the given identities.$$(\cos x+\sin x)^{2}-2 \sin x \cos x=1$$
Step 1
In this case, $a$ is $\cos x$ and $b$ is $\sin x$. So we get: $$(\cos x+\sin x)^{2}-2 \sin x \cos x = \cos^{2}x + 2\sin x\cos x + \sin^{2}x - 2\sin x\cos x$$ Show more…
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