The partial derivative with respect to $x$ is given by:
$$f_x(x, y) = \frac{\partial}{\partial x} \ln \left(4 x^{2}-y^{2}\right) = \frac{8x}{4x^2 - y^2}.$$
Similarly, the partial derivative with respect to $y$ is given by:
$$f_y(x, y) = \frac{\partial}{\partial y}
Show more…