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In Exercises 3 and $4,$ determine whether each set is open or closed or neither open nor closed.a. $\left\{(x, y) : x^{2}+y^{2}=1\right\}$b. $\left\{(x, y) : x^{2}+y^{2} > 1\right\}$c. $\left\{(x, y) : x^{2}+y^{2} \leq 1 \text { and } y > 0\right\}$d. $\left\{(x, y) : y \geq x^{2}\right\}$e. $\left\{(x, y) : y < x^{2}\right\}$

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Calculus 3

Chapter 8

The Geometry of Vector Spaces

Section 4

Hyperplanes

Vectors

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Okay, So this question we want to see if each set is either open or closed or neither. For one, the 1st 1 is closed. It is closed. The very simple reason why it's place to do that. It contains all of its boundary points because there's no inequality. It's straight equality like you itself of this one. It is open because it is not striking a quality. And if you actually brought out scene, you should be cool and it does not contain it's boundary points to defaults every more. In this one we have neither, because is closed on this one is pleasant, this one that is open on this step. So when you combine them, it's closed and rightly so. Neither. This one is very easily close because it's a strictly politics here. Well, this case is open because there is a strict quality very definitely doesn't contain. Well, it was bound

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