Question
In Exercises $35-62,$ use appropriate limit laws and theorems to determine the limit of the sequence or show that it diverges.$$a_{n}=\frac{3-4^{n}}{2+7 \cdot 3^{n}}$$
Step 1
This gives us: $$ a_{n}=\frac{\frac{3}{3^n}-\frac{4^n}{3^n}}{\frac{2}{3^n}+7} $$ Show more…
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In Exercises $35-62,$ use appropriate limit laws and theorems to determine the limit of the sequence or show that it diverges. $$ b_{n}=\frac{3-4^{n}}{2+7 \cdot 4^{n}} $$
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In Exercises $35-62,$ use the appropriate limit laws and theorems to determine the limit of the sequence or show that it diverges. $$ a_{n}=\frac{3-4^{n}}{2+7 \cdot 3^{n}} $$
In Exercises $35-62,$ use appropriate limit laws and theorems to determine the limit of the sequence or show that it diverges. $$ a_{n}=\left(2+\frac{4}{n^{2}}\right)^{1 / 3} $$
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