Question
evaluate the definite integral. Use a graphing utility to confirm your result.$$\int_{2}^{4} x \operatorname{arcsec} x d x$$
Step 1
We let $u = \operatorname{arcsec} x$ and $dv = x dx$. Then we find $du = \frac{1}{x \sqrt{x^2 - 1}} dx$ by differentiating $u$ and $v = \frac{x^2}{2}$ by integrating $dv$. Show more…
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