00:01
Hello, welcome to this lesson.
00:03
In this lesson, we'll be finding a talk that is generated by the force acting at a pivot.
00:15
Okay, so the talk is given by the magnitude of the vector p .k times the magnitude of the force, then times sine theta.
00:45
Where theta is the angle okay so this is given by but before then we've been given the magnitude of pq as eight inches and you're converting that one to fit okay so one inch is equal to 0 .0 feet foot okay okay so one inch is equal to 0 .0 8 3 3 3 3 foot so here what we do is that 8 is equal to 8 times the whole thing.
01:45
It's many times.
01:47
So the 8 inch would be equal to be equal to 8 times 0.
02:08
8 33, 3, 3.
02:11
A lot of them.
02:14
And that is a pause mainly.
02:19
Suppose what is 0 .6666.
02:24
7 feet.
02:27
Okay, so let's substitute that now you have the torque course to 0.
02:35
Okay, then we multiply by the force...