Question
In Exercises $41-46,$ use a graphing utility to graph the function. Locate the absolute extrema of the function on the given interval.$$f(x)=x^{4}-2 x^{3}+x+1, \quad[-1,3]$$
Step 1
The critical points are where the derivative of the function is equal to zero or undefined. The derivative of the function $f(x)=x^{4}-2 x^{3}+x+1$ is $f'(x)=4x^{3}-6x^{2}+1$. Setting $f'(x)$ equal to zero gives us the equation $4x^{3}-6x^{2}+1=0$. Solving Show more…
Show all steps
Your feedback will help us improve your experience
Linh Vu and 97 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
In Exercises $41-46,$ use a graphing utility to graph the function. Locate the absolute extrema of the function on the given interval. $$ f(x)=\frac{3}{x-1}, \quad(1,4] $$
Applications of Differentiation
Extrema on an Interval
In Exercises $41-46,$ use a graphing utility to graph the function. Locate the absolute extrema of the function on the given interval. $$ f(x)=\left\{\begin{array}{ll}{2 x+2,} & {0 \leq x \leq 1} \\ {4 x^{2},} & {1<x \leq 3}\end{array},[0,3]\right. $$
Finding Absolute Extrema In Exercises $41-44,$ use a graphing utility to graph the function and find the absolute extrema of the function on the given interval. $$ f(x)=x^{4}-2 x^{3}+x+1, \quad[-1,3] $$
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD