in-exercises-43-46-write-an-equation-for-the-parabola-in-standard-form-4

Name: in exercises 43 46 write an equation for the parabola in standard form 4
Uploaded: 2018-12-01
Duration: 1 min 17 s
Channel: Numerade
Description: In Exercises 43-46, write an equation for the parabola in standard form.

Question

In Exercises 43-46, write an equation for the parabola in standard form.

J Hardin · Accepted Answer

this problem, we see that the Vertex is given by the point two zero and that the Graf passes through the point three two. So if we go to the standard form recall, this is the general standard form where the Vertex is given by H. K. So in our case, using each equals two K equals zero. We can rewrite this now if we could just find the value of a we solve the problem. So let&#x27;s use this fact here, which says f of three is equal to two. So this means so plug in three and for X, and you have a Abel&#x27;s too. So just plug in that value in for a in our formula and we&#x27;LL get the standard form and here&#x27;s our final answer.

J Hardin · Answer

in this problem with were given that the Graf passes through the points minus three zero minus one for and also one zero. And also from the graph we see that this is the vertex. So since I have the Vertex we&#x27;LL call the standard form of a problem in general for tenses the point h Kama k So on our case, this becomes X minus negative one plus four Sorry for the square up there. Now we just need to find the value of a and so we&#x27;re given some information regarding the ex intercepts. So let me use this fact over here this is f a born equal zero. So f one, I could also find it by just plugging in one and for X here. So we get for a plus four. However, by the given information, we know that this is also equal tau zero. So solve this for a this equation. Now here. And now that you have your new a value, just plug your A and back into the original F to obtain the following. So have a negative outside the parentheses. X plus one square plus four. So this is our parabola and the standard form

J Hardin · Answer

and this problem Looking at the graph, we see that the Vertex is the point minus two minus one. And also that the graph passes through the point 03 So recall the standard forum of a problem where the Vertex is given by the point H comma K. Sure, so in our case, they gave us the Vertex. So this means h is minus two. K is minus one. So plugging these into the birth text form gives us this function for F. And now we just have to find the value of a and to do so we&#x27;ll use this fact over here, which is equivalent to saying f of zero equals three. So let&#x27;s plug in zero and for X here in this equation up here. And we have four a minus one. And by the given information that equals Oops, that I shouldn&#x27;t have put a zero there. That should be a three. So this means for a equals four. So a equals one and then finally, just plug in this a value back into our function. And when you do so you obtain the final answer. Yeah, So there is our parabola in the standard form

J Hardin · Answer

in this problem, we see that the Vertex on the graph is the point minus two two, and the graft passes through the points. So they gave us some excellent Recep Sa&#x27;s well. So let&#x27;s recall a few things here. What is the standard form where the vortex is the point age? Kama K. In our case, here&#x27;s our H and here&#x27;s our cake So we could rewrite this X minus negative to that becomes X plus two plus que so if we could find the value of a, the problem is complete. And so let&#x27;s use some of this information over here. Actually, we&#x27;LL just need one of these, so let&#x27;s let&#x27;s just use this one over here. Since your graph passes through the point minus one zero, that means f of negative on zero. However, we could also plug a negative one. It&#x27;s far formula over here and you get a plus two. Now, from the given information, we know that this value is also equal to zero. So saw that equation for a and then use this value of A to plug it back into your F. So replace a with minus two, and then we have our final hand, sir, in the standard form

Suman Saurav Thakur · Answer

we have 43 number. Question on given figure is like this. This is a way. This is X and the parable A passive street to three common six and definitely the vortex is at the origin. So standard a question off this type of parabola. Must be excess squarely. Call toe four p. Y. So this passes to take 14 So let us plug in X equal to three. And why Quito six? Because it just positively common. Six. So four people we call toe nine by six, that is three by two. So let us plug in four. By being back here, we will be getting our question. Access critical to three by two White. So this will be dancer. Thank you so much.

Suman Saurav Thakur · Answer

This is for the four number problem for the four number problem. Ah, given figure is like this given figure is like, this graph is like this, and it is passes through. It passes through minus two. Common six. So history question off. This type will be called to Access Square. So device square equal Do for B y. Why, Scott? It would afford PX. Okay, four picks. It passes through minus two. Common six or texas zero comma zero. His pastures to minus two. Common six. So six square equal to four p into minus two. So for people Baycol toe 36 by minus two. So mindset in. So let us plug in this value for P over here. So why squad will be called toe minus 18 x. This is the answer. Thank you. Still might

Problem

In Exercises 47-56, write the standard form of th…

Problem 46 Easy Difficulty

In Exercises 43-46, write an equation for the parabola in standard form.

Answer

$y=2(x-2)^{2}$

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