00:01
So we're looking at this function f of x here, and we want to apply the first derivative test to find any relative minimums or maximums along this open interval from 0 to 2 pi.
00:12
And the first derivative test we can apply to the values of f prime of x along certain intervals determined by the critical numbers.
00:22
And the critical numbers are found by taking the derivative of f of x and solving for 0, solving x when the function is equal to zero.
00:31
So if we find that we have f prime of x along those intervals going from negative to positive, we have a relative minimum.
00:39
And if we have f prime of x going from positive to negative, that's a relative maximum.
00:44
So what we first have to do is we have to get the derivative of f of x.
00:49
Now we can't directly take the derivative of sine x times cosine x.
00:54
But what we can do is we can use the fact that we know that sine x times cosine x is equivalent to sine of 2x divided by 2.
01:07
And so this is a function that we can take the derivative of.
01:11
And we do this by applying the chain rule.
01:14
So we'll have this function, this being f of x, rewritten.
01:21
And if we're to go ahead take the derivative, what we then end up getting is co -sounding.
01:33
2x.
01:38
So now that we have our derivative function, f prime of x, we're going to go ahead set that equal to 0.
01:48
And when we do that, we'll find a number of different values that satisfy that equation.
01:54
So going from the smallest to the largest, we have pi over 4, 3 pi over 4, 5 5 pi over 4 and 7 pi over 4.
02:20
So now we found our critical numbers and what we want to do is we want to set up the intervals that we're looking at the value of f prime of x 4.
02:29
So remember that we're looking at the open interval from 0 to 2 pi.
02:36
So that's the total amount of the interval that we're looking at.
02:42
So we have first 0 to pi of 4, and then each interval is just going to go between each of these critical numbers till the end of the open interval that we're looking at.
03:01
So we have from pi over 4 to 3 pi over 4, 3 pi over 4 to 5 pi over 4, 5 pi over 4 to 7 pi over 4.
03:22
5 over 4 to 7 pi over 4.
03:29
And then finally we have 7 pi over 4 to 2 pi.
03:43
So now what we want to do is we want to look at the sign of f prime of x.
03:48
So this means taking a value between within each of these test intervals and determining the sign...