Question
In Exercises $43-50$, find the slope and the $y$ -intercept for the graph of each equation in the given system. Use this information (and not the equations' graphs) to determine if the system has no solution, one solution, or an infinite number of solutions.$$\left\{\begin{array}{l}y=\frac{1}{2} x-3 \\y=\frac{1}{2} x-5\end{array}\right.$$
Step 1
This equation is in slope-intercept form, which is $y=mx+b$, where $m$ is the slope and $b$ is the y-intercept. So, for the first equation, the slope $m$ is $\frac{1}{2}$ and the y-intercept $b$ is $-3$. Show more…
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In Exercises $43-50$, find the slope and the $y$ -intercept for the graph of each equation in the given system. Use this information (and not the equations' graphs) to determine if the system has no solution, one solution, or an infinite number of solutions. $$\left\{\begin{array}{l} 2 x+y=0 \\ y=-2 x+1 \end{array}\right.$$
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In Exercises $43-50$, find the slope and the $y$ -intercept for the graph of each equation in the given system. Use this information (and not the equations' graphs) to determine if the system has no solution, one solution, or an infinite number of solutions. $$\left\{\begin{array}{l} y=-\frac{1}{2} x+4 \\ 3 x-y=-4 \end{array}\right.$$
In Exercises $43-50$, find the slope and the $y$ -intercept for the graph of each equation in the given system. Use this information (and not the equations' graphs) to determine if the system has no solution, one solution, or an infinite number of solutions. $$\left\{\begin{array}{l} y=\frac{3}{4} x-2 \\ y=\frac{3}{4} x+1 \end{array}\right.$$
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