Question
In Exercises $49-52,$ find an equation for and sketch the graph of thelevel curve of the function $f(x, y)$ that passes the given point.$$f(x, y)=16-x^{2}-y^{2}, \quad(2 \sqrt{2}, \sqrt{2})$$
Step 1
This gives us $$f(2 \sqrt{2}, \sqrt{2}) = 16 - (2 \sqrt{2})^{2} - (\sqrt{2})^{2} = 16 - 8 - 2 = 6.$$ So, the value of the function at the given point is $6$. Show more…
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