00:01
On this problem, we're trying to find and sketch the domain of this function f of xy is equal to 1 over the natural log of 4 minus x squared minus y squared.
00:15
Function like this, we need to consider what rules we know exist.
00:22
Our first rule is that we know that 4 minus x squared minus y squared needs to be greater than 0.
00:30
And that's because whatever we take the natural log of needs to be greater than 0.
00:38
That the denominator of this function cannot equal zero because we know that we cannot have a zero denominator.
00:47
The only way that we would end up with a zero denominator is if 4 minus x squared minus y squared was equal to 1.
00:55
So we know that that cannot be true in order for this to work.
00:58
So 4 minus x squared minus y squared cannot equal 1 because that would give us a 0 as our denominator.
01:05
So 4 minus x squared minus y squared cannot equal one.
01:10
Start by thinking about what kind of equation we're looking at here, or inequality that we're looking at here.
01:16
We're looking at something that looks similar to the inequality of a circle.
01:20
So i'm going to rearrange this so it looks like that type of inequality.
01:24
So first i'm going to add to both sides, x squared plus y squared, so that i only have my constant on one side.
01:35
When i do that, i'm left with 4 is greater than x squared plus y squared...