00:01
Suppose i need to find the integral from 2 to 6 of x plus 1 over x dx.
00:08
Now, it might be tempting to go ahead and add this fraction by turning this x into x squared over x plus 1 over x.
00:19
You get something like x squared plus 1 all over x and dx.
00:23
This actually just makes it more difficult.
00:26
So we're not going to do that.
00:27
Instead, we're going to evaluate this integral piece by piece.
00:31
So we're going to do the integral of x, and then we're going to do the integral of 1 over x, and then plug in our bounds.
00:38
So the integral of x, of course, is just x squared over 2, plus the integral of 1 over x, dx, if you recall, is the natural log of x.
00:53
Normally i would want this to be an absolute value, but because the limits are both positive, that won't matter for us at this point.
01:00
And i'm going to evaluate this from 2 to 6.
01:04
First, by plugging in the 6, and then subtracting whatever i get when i plug in the 2.
01:11
So plugging in 6.
01:13
6 squared over 2 plus ln6 minus 2 squared over 2 plus ln of 2.
01:37
Now i will evaluate this as much as i can combining like terms as i go.
01:43
6 squared over 2.
01:44
6 squared is 36, 36 over 2 is 18.
01:48
So i have 18 plus natural log 6.
01:53
And as i go, i can distribute this negative in here...