Question
In Exercises $53-60,$ find the projection of u along v.$$\mathbf{u}=\langle- 1,2,0\rangle, \quad \mathbf{v}=\langle 2,0,1\rangle$$
Step 1
The dot product of two vectors is calculated as follows: $$\mathbf{u} \cdot \mathbf{v} = u_1v_1 + u_2v_2 + u_3v_3$$ Substituting the given values, we get: $$\mathbf{u} \cdot \mathbf{v} = (-1)(2) + (2)(0) + (0)(1) = -2 + 0 + 0 = -2$$ Show more…
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