Question
In Exercises $53-64,$ complete the square and write the equation in standard form. Then give the center and radius of each circle and graph the equation.$$x^{2}+y^{2}+12 x-6 y-4=0$$
Step 1
The given equation is $x^{2}+y^{2}+12x-6y-4=0$. We can rewrite this as $(x^{2}+12x)+(y^{2}-6y)=4$. Show more…
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In Exercises $53-64,$ complete the square and write the equation in standard form. Then give the center and radius of each circle and graph the equation. $$x^{2}+y^{2}+6 x+2 y+6=0$$
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