Question
In Exercises $55-72$ , find the vertex, focus, and directrix of the parabola and sketch its graph. $$x=\frac{1}{4}\left(y^{2}+2 y+33\right)$$
Step 1
The standard form of a parabola is $x=a(y-k)^2+h$ or $y=a(x-h)^2+k$ where $(h,k)$ is the vertex of the parabola. The given equation is $$ x=\frac{1}{4}\left(y^{2}+2 y+33\right) $$ We can rewrite this as $$ x=\frac{1}{4}\left((y+1)^{2}+32\right) $$ which Show more…
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