00:04
We're asked to prove that m and m bar accept the same language in part a.
00:14
So, first, let x be a string accepted by the machine m, and let sx be the state where the string ends in x.
01:06
The string x ends in machine m.
01:11
Now, we know that x is accepted by m, so it follows that sx is a final state of m.
01:26
And by the construction of m bar, it follows that x will end at the state s x, the equivalence class containing s x, so it's the r star equivalence class containing s x in m bar.
02:15
And we have that the r star equivalence class of s x is a final state since all states in the r star equivalence class of s x are final states now this is because s x which is in the equivalence class r star containing x is a final state so it follows all the other states in r star of s x by previous problem are all final or non -final states so it follows that the r -star equivalence class containing sx is a final state in m -bar.
03:56
This implies that m and m -bar accept the same language.
04:30
Now in part b, we're asked to prove that if the machine m has the property f of s 0 x equals s for all states s and some string in i -star, then m -bar, the machine has the minimum number of states of all finite state automaton equivalent to m.
05:00
So to prove this statement, suppose that m has the property f of s not x equals s for all states s in m, and sum string x in i star.
06:38
I'm sorry, this should be written as m as the property that for all states s and s, in m, there is an x in i star such that this statement, f of s not x equals s, is true...