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In Exercises $6-14, x=12, y=10,$ and $z=24 .$ Write each ratio in simplest form. $x :(x+y) :(y+z)$

Exercises $15-20$ refer to a triangle. Express the ratio of the height to the base in simplest form. $$\begin{array}{|c|c|}\hline \text { height } & {5 \mathrm{km}} \\ \hline \text { base } & {45 \mathrm{km}} \\ \hline\end{array}$$

Exercises $15-20$ refer to a triangle. Express the ratio of the height to the base in simplest form. $$\begin{array}{|c|c|}\hline \text { height } & {1 \mathrm{m}} \\ \hline \text { base } & {0.6\mathrm{m}} \\ \hline\end{array}$$

Exercises $15-20$ refer to a triangle. Express the ratio of the height to the base in simplest form. $$\begin{array}{|c|c|}\hline \text { height } & {0.6 \mathrm{km}} \\ \hline \text { base } & {0.8\mathrm{km}} \\ \hline\end{array}$$

Exercises $15-20$ refer to a triangle. Express the ratio of the height to the base in simplest form. $$\begin{array}{|c|c|}\hline \text { height } & {1 \mathrm{m}} \\ \hline \text { base } & {85\mathrm{cm}} \\ \hline\end{array}$$

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In Exercises $6-14, x=12, y=10,$ and $z=24 .$ Write each ratio in simplest form. $z : x : y$

$12 : 6 : 5$

substituting. We have 24 to 12. 10. We know these can all be divisible by two. 12 to 6 to five.

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## Discussion

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substituting. We have 24 to 12. 10. We know these can all be divisible by two. 12 to 6 to five.

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