00:01
Item you are given that the degree of the polynomial is three.
00:07
You are given zeros negative five and four plus three i.
00:14
And you're told that when the function is evaluated at two, the function equals 91.
00:24
Let's recall that when we are trying to write a third degree polynomial or an nth degree polynomial.
00:33
The function is of this form.
00:43
And we have as many factors as the degree of the polynomial.
00:49
So let's put in the zeros.
00:54
The 8, the ace of n is just going to be carried along for just a while.
00:58
Remember that if we substitute in a negative 5 here, we're going to get a plus 5.
01:04
We substitute in the negative or plus.
01:09
Plus 3i, or i'm sorry, we subtract the 4 plus 3i.
01:13
And remember that the imaginaries come in pairs.
01:18
So this would be 4 minus 3i.
01:23
So there is a pattern that happens here.
01:26
We could do all this distribution, which would be quite lengthy.
01:33
But the pattern here is that you would multiply the xes.
01:37
You would get x squared.
01:39
You would add the negative 4, the negative 4.
01:42
This negative would be distributed.
01:45
So we're going to get negative 8...