00:02
We're going to start by finding the slope of the given line, and so we can isolate y, and we get y equals the opposite of x plus 7, so the slope of that line is negative 1.
00:13
So for part a of the problem, we're looking for the line that's parallel to this and through the given point.
00:18
So parallel lines have the same slope, so the slope will again be negative 1, and we'll use the point, negative 3, 2, and let's go ahead and use point slope form, and we'll substitute negative 3 in for x1 and 2 in for y 1 and negative 1 in for m so we have y minus 2 equals negative 1 times x minus negative 3 and we'll simplify that so y minus 2 equals negative 1 times x plus 3 we'll distribute the negative 1 y minus 2 equals the opposite of x minus 3 and we'll add 2 and we get y equals the opposite of x minus 1 so that line is parallel to the given line and then for part b, perpendicular, we're going to use the negative reciprocal slope, and the negative reciprocal of negative 1 is positive 1, and we're going to use the same point, negative 3, 2.
01:13
And again, let's use point slope form, where negative 3 is our x1, 2 is our y1, and our slope is 1...