Question
In Exercises $7-12,$ identify the center and radius of the circle. $$x^{2}+(y+12)^{2}=24$$
Step 1
This is the standard form of the equation of a circle, where $(h,k)$ is the center of the circle and $r$ is the radius. The given equation is $x^2 + (y+12)^2 = 24$. We can rewrite this as $(x-0)^2 + (y-(-12))^2 = \sqrt{24}^2$. Show more…
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