00:01
Okay, so this question asked to find the first five terms of this infinite sequence.
00:06
First term is given to a1 is equal to six, and then to find out the rest, we're given this formula, which is a subk plus 1 equals 1 3rd, a subk squared.
00:19
So essentially what we're going to do is plug in the last value of the sequence in for ak to find the next one, which would be a.
00:30
Sub k plus 1.
00:32
This will be more clear once we go through the actual problem.
00:36
So we're given a1 already, so the next one we need to find is a2.
00:43
Now, a2 is just a1 plus 1.
00:51
So i'm just substituting in a subk plus 1 to show that what we're using as ak is really just this, which is a1, in 4.
01:06
What this value is going to be a sub k.
01:09
So we'll get one -third quantity.
01:13
Remember, ak is just the last value of the sequence, which would be a1, which we know is 6.
01:21
That value is squared.
01:24
So then we have one -third of 36, which is just 12.
01:31
So a2 is equal to 12.
01:34
Now we'll use a2 to find a3, because remember again, if we're finding a3, we look at this formula right here.
01:47
If we're trying to find a3, then we have to use the previous term of the sequence, which is a2, square that value and then divided by 3.
01:57
So same process again...