00:01
Using the x and y coordinates out of one single point, we want to figure out which quadrant we could use points that would satisfy a condition of x cubed being greater than zero.
00:18
At the same time, y cubed is less than zero.
00:23
So to fit this condition, when you cube a number, you're going to have three positive signs or three negative signs.
00:34
So for x cubed to be greater than zero, x must be positive.
00:43
And for y cubed to be less than zero, we need an odd number of negative signs, which means y would have to be negative.
00:53
If we look at our quadrants, in quadrant 1, both x and y are positive.
01:00
In quadrant 2, x is negative and y is positive.
01:04
If i multiply them, i'd have a negative outcome, but it doesn't fit our condition...