00:04
Hello, we're given an equation of a parabola which is x squared plus 6y equals 0.
00:20
So this is going to be a parabola.
00:25
So we will have a look at theorem 101.
00:29
Let's have a look at theorem 101 says.
00:32
It says that the standard formula for a parabola is when one of the variables is squared and the other is not.
00:45
So we see that the variable x is squared here and here the variable y is squared.
00:51
So this is not going to be the case.
00:54
We are going to focus on the case where there is a vertical axis.
01:00
Okay, theorem 10 tells us that the focus is below or above the the vertex the vertex v has coordinates hk okay so this vertex v it will the problem will open up or down depending on whether this parameter p in the standard equation is positive or negative okay so let's see what do we have here we have this is our formula it hasn't been written in the standard form so what we will do is we will subtract minus 6y to get x squared equals minus 6 y now we have we have the situation where the x is x minus 0 squared and this is minus 6 minus 6 times y minus 0 now this minus 6 we can write as we can write this minus 6 as we can write this minus 6 as it is negative it's negative but it's four times six over four okay four and four cancels and this is so this is our p it's negative p is equal minus six fourths or it's equal minus three halves so this is negative we will have we will have the situation where the parabola opens down.
02:43
It will open down.
02:46
We forget about this situation here.
02:51
And we also have found that the vertex is at h is equal 0 and k is equal 0.
03:00
Therefore the vertex is at 0.
03:03
We have found the vertex.
03:06
The focus, the focus is the focus is the focus is at a point h, okay, 0, 0 plus what is the p minus 3 half.
03:22
So 0 minus 1 .5...