In Exercises, explain the mistake that is made.
Given the functions $f(x)=|x-A|-1$ and $f(1)=-1,$ find $A$
Solution:
since $f(1)=-1,$ the point $(-1,1) \quad-1=|-1-A|-1$
must satisfy the function.
Add 1 to both sides of the equation. $\quad|-1-A|=0$
The absolute value of zero is zero, so there is no need for the absolute value signs: $-1-A=0 \Rightarrow A=-1$
This is incorrect. What mistake was made?