00:01
So here, for part a, we are going to use equation 12 .8, and we can then, this leads to t sub 1 times sine of 40 degrees.
00:12
This would be plus t sub 2 times sine of theta.
00:17
This is equaling the weight m .g.
00:20
We also know that then equation 127 will lead to t sub 1 times cosine of 40 degrees minus t sub 2.
00:32
To cosine of theta, this is equaling 0.
00:36
So essentially we're going to combine these equations and then solve for t sub 2.
00:40
So t sub 2 would then be equaling mg divided by cosine of theta, multiplied by tangent of 40 degrees plus sign of theta.
00:56
In order to minimize this, we can plot this or we can take the derivative and set this to zero.
01:04
In any case, whether plotting or taking the derivative setting equal to zero, we find that here, theta is going to be equaling 50 degrees...