00:01
So for part a, we know that here the volume of water during the first 10 minutes would be equal to the volumetric flow rate.
00:07
This would be equal to v sub 1 times t times a sub 1, where v sub 1 times a sub 1 would be the volumetric flow rate and then times t would give us the total volume v.
00:22
So this would be equal to 15 meters per second.
00:26
We're going to multiply this by 10 minutes.
00:28
10 minutes, there are 60 seconds per minute, so we have 600 seconds, and then this is going to be divided by pi over 4, multiplied by the diameter squared, 0 .03 meters, quantity squared, and for part i, we have a volume of 6 .4 cubic meters.
00:49
For part b, we know that the speed in the left section of the pipe, v .2 would equal v sub 1.
00:57
The speed in the right section of the pipe, multiplied by a sub 1 divided by a sub 2.
01:04
So this would be equal to v .1, multiplied by d sub 1, divided by d sub 2, quantity squared.
01:12
This would be equal to 15 meters per second, multiplied by 3 .0 centimeters, by 5 .0 centimeters quantity squared and this is equaling 5 .4 meters per second this would be the speed in the left section of the pipe...