Question
In Fig. $25-53, V=12 \mathrm{V}, C_{1}=C_{4}=$$2.0 \mu \mathrm{F}, C_{2}=4.0 \mu \mathrm{F},$ and $C_{3}=1.0 \mu \mathrm{F}$What is the charge on capacitor 4 ?
Step 1
Capacitors $C_1$ and $C_2$ are in parallel, as are capacitors $C_3$ and $C_4$. We can find the equivalent capacitance for these pairs using the formula for capacitors in parallel: $C_{eq} = C_1 + C_2$. This gives us $C_{eq1} = 2.0 \mu F + 4.0 \mu F = 6.0 \mu F$ Show more…
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