00:01
All right.
00:03
So for this problem, we have the circuit.
00:09
So we have the c1 here.
00:12
We have three parallel connected c2, c3, c4.
00:24
And we have the other two parallel connected c5, c6.
00:33
So yeah, that's all.
00:36
And this is v.
00:37
So we know the parameters v is 12 volts.
00:41
C1.
00:41
C6.
00:42
C1 is c1 equals c5, equals c6, 6 microferrales, and c2 equals c3 equals c4, which is four microferrales.
00:56
So for part a, we want to find out the charge stored on the whole capacities.
01:02
So that is equivalent to say that we need to find out the equivalent capacities of the whole circuit.
01:09
So, c2, c3, c4, they are connected in parallel.
01:16
So basically, c2, 3, 4 equal to c2 plus c3 plus c4, which equal 12 micro -fadres.
01:26
And c5, 6, they're also in parallel, right? so this is c5 plus c6.
01:33
So this is 12 either, 12 microferiorities.
01:37
And this c5, 6, and the c2, 3, 4, they're in series.
01:43
So basically, c2, 3, 4, 5, 6 equal, because this is 12 and this is 12 either.
01:51
So this is just a half times 12, which is 6 micro -feriorities.
01:58
And combined with the c1, so c total, i just say ct.
02:03
C total will be equal to, yeah, c1 is also equal to 6.
02:08
C1 and 6 micro -fairdates, right? so c total is equal to half times 6 equal to 3 micro -ferrales...