00:01
For this problem on the topic of magnetic fields, we are shown two ends of a u -shaped wire, which has a mass of 10 grams and a length of 20 centimeters.
00:08
Both ends are immersed in mercury, and the wire is in a uniform field, which has a magnitude of 0 .1 tesla's.
00:15
A switch is then rapidly closed and reopened, which sends a pulse of current to the wire, and causes the wire to jump upward.
00:22
We are told that the wire jumps up by height of 3 meters.
00:25
We want to calculate the amount of charge that was in the pulse.
00:28
Now the magnetic force exertion on the u -shaped wire is given by f is equal to the current i tends the length of the wire l times the field strength b.
00:39
If we use the impulse momentum theorem, we have the change in momentum delta p equal to m delta v for the wire, which is the integral of f d t, which is the integral of i .l b d t, which is the integral of i .l b d t, which is the, which is l times b, which are both constant, times the integral of i d t.
01:08
We know that the integral of idt is simply the charge q.
01:12
So this is l times b times the total charge q in the pulse...