00:01
Currents i, 2 .2 ampere, is set in a long hairpin conductor found by bending a wire into semicircle of radius 8 .5 m m.
00:11
Point b is midway between the straight sections and so distant from the semicircle that each straight section can be approximated as infinite wire.
00:21
Then what are the magnitude and direction of the magnetic field at 8? and magnitude and direction of the magnetic field at b magnetic field at point a consists of the magnetic field due to semicircle and due to semi -infinite wire for semicircle it is nu not i pi by 4 pi r which is equal to new not i by 4rr now this infatimal magnetic field for semi -infinite equals mu not i d x i cross r cap divided by 4 pi into r square this will be equals to nu not i r by 4 pi into d x by r squared plus x squared raised to the power 3 by k cap.
01:42
The value of x ranges from 0 to infinite therefore integrating it within the limits of 0 to infinite we get the magnetic field for the sine infinite is nu not i r by 4 5 integrating from 0 to infinite d x by r square plus x squared raised to the power 3 by 2 k cap here x equals r tan theta then d x will be equals to r s square theta d theta then r sq square square plus x square can be written as r squared sec square theta using this into the equation we have the integral of d x by r square plus x square raised power 3 by 2 k cap equals 1 by r square x divided by root of x square plus r square k -capped plus constant.
02:58
Evaluating the integral from 0 to infinite, the magnetic field is equals to equals nu not i by 4 pi r k -cap.
03:13
Interestingly this is half of the magnetic field due to infinite wire.
03:18
Two long segments have a magnetic field along positive z direction, therefore due to the ranked and rule.
03:25
And we have the magnetic field at point a, b, a equals nu0i by 4r, 1 plus 2 by pi as it is the addition of semicircle plus twice of 2 semi.
03:48
Now substituting the values into the equation 1 plus 2 by pi into 4 pi into 10 raised to the power minus 7 into current is 2 .2 ampers divided by 4 into r is 8 .5 and 1 that is 10 raise to the power minus 3 must be multiplied...