00:01
Hi there.
00:03
So for this problem, we need to calculate the net force that is produced in the wire four because of the other three wires.
00:16
In this case, we are going to use the magnetic force that is in this point for and then zoom all of the components.
00:30
So what i'm going to do is to draw all the forces that the wire 4 fills because of the wire 1, 2, and 3.
00:44
So to do that, we can see, we know that when two wires have the same direction in current, they attract each other.
00:56
So in that sense, the force that feels the wire four because of one is in this direction to that curve, to that wire.
01:13
Now, the force that feels, the wire, four because of three, goes to the left because it feels, it feels an opportunity.
01:29
An opposite force because they have an opposite direction in their current.
01:34
So this is 4 and 4 3.
01:41
And the other one goes in the line that connect them.
01:47
And this is also in the opposite direction because they have different directions in current.
01:56
So this is 4 -2.
02:00
Um, so this is 4 -2.
02:02
Um, so the net force that it is filled in 4 that we call it like this, it's just the superposition of all of these forces that we will have for 1, 4 2, 4 3.
02:26
And this angle in here, we can easily obtain it because we know that this, this, this, these wires form a square, sorry, form a square, and each edge has a length of 30 .5 centimeters.
02:55
So in that sense, this in here forms 45 degrees because it is half of 90 degrees that is what it forms the x axis with the y axis.
03:13
So we have that angle that we are called teta 45 degrees.
03:21
So we start by calculating each company of these f4 force.
03:32
So the companies that we are going to call it components.
03:40
In this sense we have the fours company.
03:44
So we are going to take into account only the forces that are acting on the ad acids or at least have some component on it.
03:55
So we have minus f43 because it is only in the component of that.
04:11
So this is just that.
04:14
And we also have minus 4 -2.
04:18
And we can see that this angle in here corresponds to this angle in here.
04:25
So it is also minus, but to obtain the x component, we need to multiply this by cousin of teta.
04:34
So having all of this, we can apply the definition for the magnetic force.
04:45
We know that that is given by the following.
04:50
Nuisance 0, the current i squared 2 pi a for this case, because from 0 .4 to 0 .3, this distance is a, which is this, but we are going to call it a.
05:14
So that's why we put this in here, minus the other one, epsilon 0, y, casino 40 degrees, this value in here, and over the distance pi a times the distance to, oh no, okay, i'm pretty like this.
05:43
The distance from the point four to the point two, we can calculate it by just using the hypotenuse.
05:54
We know that this in here is a, and we know that this in here is a.
06:00
So the hypotenuse is the square root of two times a, and that's the thing that we are going to put in here.
06:16
So that is 2 pi a the square root of 2.
06:38
So this is what we have for the s component of the force that is acting on the wire.
06:48
Now we do the white component.
06:54
So the white component in this case, we write it like this or want because it only has a vertical component, so it is simply that minus f2, and in this case, the component is given by the sign of theta, because we want the vertical component.
07:36
So it's sign of theta and it is minus because it is pointing downwards.
07:41
So it is minus.
07:43
And here we again apply the definition for the magnetic force.
07:50
So in this first case is mucus 0.
07:58
And the distance to the wire 1 is also a, so it's 2 pi a minus the one from the and this is here.
08:26
So we sum this...