00:01
So we're going to be looking at problem 22 of chapter 5 of the physics 5th book.
00:06
The question says, a is a 4 .4 kilogram block and b is a 2 .6 kilogram block.
00:12
The coefficients of static and kinetic friction between a and the table are 0 .18 and 0 .15.
00:19
Part a determined the minimum mass of block c that must be placed on top of block a to keep sliding.
00:24
And if part b, if block c is suddenly lifted off, what is the acceleration of block a? this is the setup we have.
00:32
We have some block a here and it has some block c on top of it, which we don't know the mass of.
00:38
The massive block a is 4 .4 kilograms.
00:43
Mass of block b is 2 .6 kilograms.
00:48
And they both have weight of b is equal to mb times g and the weight here, w here is equal to d times m a plus mc and we've got our normal force here and our friction force going backwards here and we've also got tension in the we've got tension in the ropes we've got tension in the ropes which is caused by the mass pulling downwards so we have tension here, we have tension here which is pulling a along this way so to stop a sliding, we require that the friction force is greater than or equal to the tension.
01:34
Let me just make sure these two equal.
01:41
So, f is of course equal to mu n or mu s n...