In Fig. $6.18$, if $\mathrm{LM} \| \mathrm{CB}$ and $\mathrm{LN} \| \mathrm{CD}$, prove that
$\frac{\mathrm{AM}}{\mathrm{AB}}=\frac{\mathrm{AN}}{\mathrm{AD}}$

Answer

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Geometry

NCERT Class 10 - Math

Chapter 6

Triangles

Section 2

$\quad$ Similar Figures

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Video Transcript

We are going to do problem number three discussion. There is given figure. Okay. And it is given that L. M. Is parallel to C. B. Another thing is given that Ln is parallel to city. So we need to prove died. That to prove you need to prove that I am by A B. This is equals to A N by 80. Okay, now we know by letters just right here proof, you know Cura 6.1. Okay. We just said that if any line intersect site of a triangle and that line is parallel to the other side of the triangle here elements parallel too busy so they will divide in The same ratio. So we can write as 46.1 and triangle that we writer in triangle A. B. C. That I am bye A. B. That will be equals two L by AC. I decided to ask the question # one. Similarly in triangles in triangle sed you can buy it end Bye. And by A. D. That will be equals two. L. By A C. Okay, let's just take a question # two. Now, let us compare the question on any question to. If you compare the question when any question to S. L. By A C. One side is equal in both cases, so other side will be equal the servant real sequel. So you can buy the hair that am by a bee. That is equals to a N. Bye Eddie. Okay, so this is the proof in this case Disproved. That's all. Thank you.

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