Question
In Fig. 8-51, a block slides down an incline. As it moves from point $A$ to point $B$, which are $5.0 \mathrm{~m}$ apart, force $\vec{F}$ acts on the block, with magnitude $2.0 \mathrm{~N}$ and directed down the incline. The magnitude of the frictional force acting on the block is $10 \mathrm{~N}$. If the kinetic energy of the
Step 1
This is given by the formula $W_{f} = F_{f} \times d$, where $F_{f}$ is the frictional force and $d$ is the distance. Substituting the given values, we get $W_{f} = 10 \, \text{N} \times 5.0 \, \text{m} = 50 \, \text{J}$. Show more…
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In Fig. $8-51$ , a block slides down an incline. As it moves from point $A$ to point $B,$ which are 5.0 $\mathrm{m}$ apart, force $\vec{F}$ acts on the block, with magnitude 2.0 $\mathrm{N}$ and directed down the incline. The magnitude of the frictional force acting on the block is 10 $\mathrm{N} .$ If the kinetic energy of the block increases by 35 $\mathrm{J}$ between $A$ and $B$ , how much work is done on the block by the gravitational force as the block moves from $A$ to $B ?$
In Fig. 8-51, a block slides down an incline. As it moves from point $A$ to point $B$, which are $5.0 \mathrm{~m}$ apart, force $\vec{F}$ acts on the block, with magnitude $2.0 \mathrm{~N}$ and directed down the incline. The magnitude of the frictional force acting on the block is $10 \mathrm{~N}$. If the kinetic energy of the block increases by $35 \mathrm{~J}$ between $A$ and $B,$ how much work is done $\mathrm{on}$ the block by the gravitational force as the block moves from $A$ to $B ?$
In the figure below, a block slides down an incline. As it moves from point A to point B, which are 5.0 m apart, a force F acts on the block, with magnitude 2.5 N and directed down the incline. The magnitude of the frictional force acting on the block is 10 N. If the kinetic energy of the block increases by 41 J between A and B, how much work is done on the block by the gravitational force as the block moves from A to B? Additional Materials Section 8.5
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