00:01
Calculating the slope for part a to find a spring constant.
00:03
This would be equalling to delta y over delta x.
00:07
This would be equaling to 5 .00 neutrons minus 0 .00 newtons.
00:14
This would be divided by 0 .20 meters minus 0 .00 meters, giving us essentially 5 .0 newtons divided by 0 .20 meters.
00:35
Now, here we can say that f sub 1, we're going to let f sub 1 equaling the spring constant multiplied by d sub 1.
00:47
And we know that then d sub 1 equaling 0 .2 0 meters.
00:53
And from the graph, f sub 1 is around 5 newton.
00:56
So k sub 1, or other my apologies, k, equalling f sub 1 divided by d sub 1, equalling, again, 5 .00, nuisance.
01:10
2 .0 meters, we can see that it's the same.
01:13
And this is giving us approximately 25 newtons per meter...