00:01
Okay, so in this problem, we have this capacitor set up.
00:04
So we have first the path branches from a to these two capacitors.
00:12
It comes back together.
00:17
Here's b.
00:19
And then here's d.
00:21
Here's c1.
00:23
Here's c2.
00:25
Here's c3.
00:27
We're told the voltage between a, b is 120 volts.
00:35
And then we're told c1 is equal to 150 or excuse me, 3 micro -farrad.
00:54
And we're told that the charge on capacitor 1 is 150 micro -coulones.
01:04
So q1 equals 150 micro -micro.
01:13
Oops, it's a little bit of lag here.
01:17
10 to the minus 6 coulomes.
01:20
And our goal is to find the voltage across the other two capacitors.
01:26
So let's play around with this one.
01:29
Oh, yeah, i'm sorry.
01:30
This one more thing.
01:32
It's q1.
01:36
So just to kind of zoom out, let's go over the main principles we're going to use.
01:40
I'm just going to state them.
01:43
I think the video will get too long if i try to prove them.
01:45
There should probably be some nice explanation in the book.
01:50
Capacitors in parallel have the same voltage, just like any two elements in parallel, and then capacitors in series have the same charge, or networks in series have the same charge more generally.
02:05
So let's see if we can use those principles to go around and fill in some information.
02:11
So the voltage across, i'm going to start with c1 and c2, so they're going to have the same voltage.
02:17
So v1 equals v2.
02:20
So that means c is q over v, so v is q over c.
02:26
So that's q1 over, excuse me, that should be c.
02:34
So b is q1 over c1 equals q2 over c2.
02:41
So we can get that q2 is just the ratio of c2 over c1 times q1.
02:48
Oh, do we have, we don't actually have the, we don't actually have the capacitance of the other of c2.
03:04
Is that correct? okay, so we're going to have to do this more with formulas.
03:11
So q2 is equal to c1 over c2, c2 over c1 times q1.
03:33
Yeah, let's see...