00:01
Okay, i've got a rough sketch of this situation here, and i'll explain my sketch.
00:05
We've got the mug that is 8 .9 centimeters tall.
00:09
And when that mug has nothing in it, the coin is out of view.
00:16
And we use that information to get this straight line from the eye down here to point b for the width of the mug, which is 6 .5 centimeters.
00:24
And when that mug is filled with water, the rays or the, um, the, the, um, the, the, the, um, the, the view that we have is refracted due to the index of refraction with water and how it bends the rays.
00:38
So we're going to use that information in a little bit of geometry in order to figure out the diameter of this coin that comes into view when the mug is filled with water.
00:48
So to get started, we want to figure out this length right here of the hypotenuse in order to use and then we use that information in order to figure out this angle of reflection here.
01:05
This angle of reflection is equal to this angle down here.
01:10
They're just complementary angles or congruent angles.
01:15
So we'll use pythagorean's theorem to solve for the length of a, b.
01:22
Pythagorean's theorem is one side squared plus the other side squared.
01:28
Is equal to the hypotenuse squared.
01:33
And we can rearrange this to solve for the length of the hypotenuse square root of a .c squared plus cb squared.
01:45
And then when i substitute in my values, 8 .9 squared plus 6 .5 squared.
01:55
And you square root all of that, you get 11 .01 centimeters.
02:00
So that is the length.
02:02
Of our hypotenuse.
02:04
Now we can use that information.
02:06
I want you to recall something from way back when called sokotoa.
02:10
Sokotoa looks like this.
02:14
It helps us remember how we can use sine, cosine, and tangent.
02:19
So the sign of the opposite length divided by the length of the hypotenuse would tell us this angle.
02:28
So that's what we do next.
02:34
The sign of this angle is equal to.
02:40
The length of c -b divided by the length of a -b.
02:47
So we take 6 .5 divided by 11 .01, that gives us 0 .59.
02:59
And we don't even have to solve for just this angle because we can substitute this in to snell's law whenever we do that, which is next...