00:02
So in this problem, we've been asked to find p gas in atmospheres.
00:10
We're using an open -ended monometer, which is pictured here, and we are given that atmospheric pressure is equal to 738 .5 tor.
00:27
We are also given the change in height of the mercury is 2 .33 .3 .3 .4 .2.
00:36
Centimeters.
00:41
So if we view the diagram, we can tell that the gas pressure is less than atmospheric pressure.
00:59
And we can tell this because of the liquid mercury.
01:06
We can see that the liquid mercury is lower on the side of the atmospheric pressure than it is on the side of the gas pressure.
01:22
So the gas pressure is less than, exerting less force onto the mercury than the atmospheric pressure is.
01:41
So this tells us that in order to find our gas pressure, all we need to do is.
01:52
Is take the atmospheric pressure, which was given to us, and subtract the change in height.
02:07
If this had been the other way around, where the gas was greater than the atmospheric pressure, we would simply be adding the change in height instead.
02:24
Now our atmospheric pressure has been given to us as 738 .5 toll.
02:31
But we are working here in millimeters of mercury.
02:40
So you may recall that one tor is equal to one millimeter of mercury.
03:01
So it's a simple one -to -one conversion...