00:01
So for this question, we want to find the oxidation state of oxygen.
00:06
So looking at this first one, we're going to set up our little oxidation equations.
00:10
That makes it easy for us to find our missing oxidation state.
00:13
So since we're looking for oxygen, we have one oxygen in this case.
00:19
We have two fluorines, however.
00:24
And we know fluorine to have an oxidation state of negative one based on our rules and where it is on the periodic table.
00:29
And this is a neutral atom.
00:32
So we find x equals a positive 2.
00:38
So for a, oxygen has an oxidation state of positive 2.
00:45
So we're going to do the same thing for b, except if we have two oxygens, we still have our two fluorine.
00:55
It's still neutral.
00:56
In this case, we find x to be a positive 1, which makes sense because it's 2x.
01:02
This is it just a single x.
01:05
Find for b, the oxidation state of oxygen is a positive one...