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In Millikan's oil-drop experiment, one looks at a small oil drop held motionless between two plates. Take the voltage between the plates to be 2033 $\mathrm{V}$ , and the plate separation to be 2.00 $\mathrm{cm} .$ The oil drop (of density 0.81 $\mathrm{g} / \mathrm{cm}^{3} )$ has a diameter of $4.0 \times 10^{-6} \mathrm{m} .$ Find the charge on the drop, in terms of electron units.
$2.21 \times 10^{-18} \mathrm{C}$
Physics 103
Chapter 30
Atomic Physics
Cornell University
University of Michigan - Ann Arbor
Simon Fraser University
Lectures
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So, uh, an oil droplet located, um, between the put metal plates is in an actor equilibrium. So, uh, we have a mentally the metal plates and Terry's, uh, the old droplet, Uh, and on the droplets, the gravitational force is one that is acting and, uh, in other forces electrical force, which compensates the gravitational first. So we have MG and Q E where e is an electric field. No, inside between us plates. So and we know that, Walt, it's between this plates is you. We also know that distance between between this place plates is, uh d So we know, Dean. We also know the density off boy. Uh, and we also know diameter to stop it. And real so no. And this free for acceleration. Q. So first thing we should write is the equatorial condition. So N g is q e, uh, aimed toward his end. We don't know my aim myself. Uh, they always go, but we know that an generally is density modified on, uh, Walden. We don't know, will you? But we know, uh, the diameter off the drug, but so we can right? The He's I mean, the cube over six This is the formula. Wait. No, that wanted to off. It's fair. Uh, this veritable doing is this. And we can plug this here and then plan this. I am here, so we will get, uh, room and then comes easy. Defend world incomes be But he is You need q former seeks and then comes to you only right side Q And they're happy, but we don't know e what is their field? But we know that a electric field generally it's world inch derided by distance Do Let's just plug these in here. Here. So we get Q and instead of e, we have you d and we want to find Q and we can do that. And Q he comes being see you, Jeanne can't be d over seeks you and we know everything. Uh, but oh, um, so we usedto so well, So we have everything we need and made sure that use sa units. So, in this problem, uh, we have quantities in different responsible sent emitters and make sure that in converts and calculates que in S i u it's otherwise you love not gets, uh, occurred cancer or even a bit an answer you defend your it. So here in beautiful Hey, should I lied? 810 uh, kilogram meter, Cute cube. And so on the way. No, I d He's given in Santee meters. It's two centimeters bread. You should also convert in meters off. This is zero problems here, two meters and you is given in inside units. So we just plugged his number. No, you choose so well. How about 33 folds? And so one last thing D S O D cube is for and like six meter and cute. So these quantities giving meters. But it is, sir, in the third power and the seas. Uh, for in this their power is 64 and 10 years meter Q. So and one more suggestion is that Levi's 10 10 power alone incalculably are the numbers. And, um then right down this temps, our next two number. So the results woman to be two points 61 10 years 18 or meet us
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