00:01
All right, so in this problem, we have keyboard, and for each key, we know that the area is 42 millimeters squared.
00:13
And the initial separation before we are pressing the key is d0, which is 0 .7 millimeters.
00:23
Okay? so we can determine the capacitance before we press this key.
00:30
So that gives us the expression c equal epsilon, a over d.
00:36
So this is the expression for the parallel plate capacitance.
00:40
So you just simply plug in the value of this a and the d, and you come to the capacity c.
00:46
So this gives you 0 .531 picofaradase, all right? so this is part a.
00:54
And in part b, so we want to know that if the if the change in the capacitance is 0 .25 picofal ferreides, we want to know the separation change of the key.
01:08
So basically we know a new capacitance c equal c plus 0 .25 picofal ferritus, right? so this gives you 0 .781 picofal ferritus, yeah...